The definite integral calculates the accumulated area under a curve over an interval. This topic introduces the concept using Riemann sums, then applies the Fundamental Theorem of Calculus to evaluate integrals exactly using antiderivatives.
\int_a^b f(x) dx
gives the net area between f(x)
and the x-axis from x = a
to x = b
F
is an antiderivative of f
, then \int_a^b f(x) dx = F(b) - F(a)
\frac{d}{dx} \int_a^x f(t) dt = f(x)
\int_a^a f(x) dx = 0
\int_a^b f(x) dx = -\int_b^a f(x) dx
\int_a^b [f(x) + g(x)] dx = \int_a^b f(x) dx + \int_a^b g(x) dx
F(b) - F(a)
. Don't forget parentheses when substituting!
\int_1^4 (2x + 1) dx
Antiderivative of 2x + 1
is x^2 + x
F(4) = 16 + 4 = 20
; F(1) = 1 + 1 = 2
Final Answer: 20 - 2 = 18
F(x) = \int_0^x \cos(t) dt
. Find F'(\pi/3)
By the Fundamental Theorem Part 2: F'(x) = \cos(x)
Final Answer: \cos(\pi/3) = 1/2